b^2-b+3=5

Solution for b^2-b+3=5 equation:

Simplifying
b2 + -1b + 3 = 5

Reorder the terms:
3 + -1b + b2 = 5

Solving
3 + -1b + b2 = 5

Solving for variable 'b'.

Reorder the terms:
3 + -5 + -1b + b2 = 5 + -5

Combine like terms: 3 + -5 = -2
-2 + -1b + b2 = 5 + -5

Combine like terms: 5 + -5 = 0
-2 + -1b + b2 = 0

Factor a trinomial.
(-1 + -1b)(2 + -1b) = 0

Subproblem 1
Set the factor '(-1 + -1b)' equal to zero and attempt to solve:

Simplifying
-1 + -1b = 0

Solving
-1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = 0 + 1
-1b = 0 + 1

Combine like terms: 0 + 1 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {-1, 2}